If there are 22 teams playing then there are 11 games. Assuming that the palray is such that there WILL be a winner (ie no draws) then there are two possible results for each game .. a win or a loss (Team A Wins – Team A loses). So there are a total of 2^11 possible combinations each round.

If a draw is possible then there are 3^11 possible combinations W – D – L on each game (Team A Wins – Team A Draws -Team A Loses).

P(all correct) = 1/2^11
= 1/2048
? 0.05%

If a draw is possible then there are 3^11 possible combinations W – D – L on each game (Team A Wins – Team A Draws -Team A Loses).

Then P(all correct) = 1/3^11
= 1/177147
? 0.0006%